For loop that takes turns between printing one thing or the other python-CodePudding

Not sure how else to word the title, but this is what I need:

Print either the number zero, the number one or a phrase in no consecutive order twenty times. This is what I have:

    n = 0
    x = “hello”
    for i in range(20):
        print(n, end= ‘’) or print(n 1, end= ‘’) or print(x)

The only problem is that it prints them out in order so that it is always 01hello01hello01hello and so on. I need it to be randomized so that it could print something like 000hello1hello101 or just any random variation of the three variables.

Let me know how :)

CodePudding user response：

import random
choices = [1, 0, "hello"]
for i in range(20):
    print(random.choice(choices))

CodePudding user response：

Your question is hard to understand, but I think this will help. If you want to randomize, then try importing random

import random
my_strings=["foo", "bar", "baz"]

for i in range(10):
    print(random.choose(my_strings))

CodePudding user response：

Use random.choice:

import random
choices = (0, 1, "hello")
print(''.join(str(random.choice(choices)) for _ in range(20)))

CodePudding user response：

The "random" module is very useful for these situations, especially the "shuffle" function.

The "suffle" function allows you to shuffle a list, this function requires the list, and optionally a function that returns a random number between 0 and 1 (by default random.random). This function does not return a list but modifies it.

import random

# Create 20 elements of each vars
vars_0 = ["0"] * 20
vars_1 = ["1"] * 20
vars_2 = ["hello"] * 20

# Join the elements
super_list = vars_0   vars_1   vars_2

# Mix the super list
random.shuffle(super_list) 

# Convert the list to a string
print("".join(super_list))

The result

hellohello001hello01hellohello1hello10hello011101hello1101hellohellohello1001hello100001hello101hello00hello0hellohellohellohello1001hello10

I think it is quite readable solution