Print all the "a" of a string on python-CodePudding

I'm trying to print all the "a" or other characters from an input string. I'm trying it with the .find() function but just print one position of the characters. How do I print all the positions where is an specific character like "a"

CodePudding user response：

You can use find with while loop

a = "aabababaa"
k = 0
while True:
    k = a.find("a", k) # This is saying to start from where you left
    if k == -1:
        break
    k  = 1
    print(k)

CodePudding user response：

This is also possible with much less amount of code if you don't care where you want to start.

a = "aabababaa"

for i, c in enumerate(a): # i = Index, c = Character. Using the Enumerate()
  if ("a" in c):
    print(i)

CodePudding user response：

Some first-get-all-matches-and-then-print versions:

With a list comprehension:

s = "aslkbasaaa"

CHAR = "a"
pos = [i for i, char in enumerate(s) if char == CHAR]
print(*pos, sep='\n')

or with itertools and composition of functions

from itertools import compress

s = "aslkbasaaa"

CHAR = "a"
pos = compress(range(len(s)), map(CHAR.__eq__, s))
print(*pos, sep='\n')