I have a data frame that looks like this:
library(tidyverse)
date = seq(as.Date("2022/1/1"), as.Date("2022/1/12"), by = "day");date
v1 = rnorm(12,0,1);length(date)
v2 = rnorm(12,10,1)
df = data.frame(date,v1,v2);df
date v1 v2
1 2022-01-01 -0.27742001 10.649777
2 2022-01-02 0.45117594 9.552337
3 2022-01-03 -0.57960540 8.377525
4 2022-01-04 0.03795781 9.016521
5 2022-01-05 -0.58670684 10.893805
6 2022-01-06 -0.10260160 10.445416
7 2022-01-07 -0.31061137 9.863794
8 2022-01-08 -0.01944977 8.859400
9 2022-01-09 -0.33269714 10.035201
10 2022-01-10 0.38196430 9.953147
11 2022-01-11 0.72070334 8.328117
12 2022-01-12 -0.71014679 8.046312
i want to plot the column v2 in the secondary axis.How can i do this in R?
my effort is the following:
p = ggplot()
geom_line(data =df,aes(x=date,y=v1),size=1)
scale_x_date(date_labels="%d",date_breaks ="1 day")
scale_y_continuous(sec.axis = sec_axis(v2, name="v2"));p
but reports me an error :
Error in `sec_axis()`:
! Can't convert `trans`, a double vector, to a function.
Any help ?
CodePudding user response:
To plot your second column add a second geom_line
. And to fix the error you have to pass a function to the first argument of sec_axis
aka the trans
argument. This function is used to transform the range of the primary axis. If you don't need any transformation then use the identity function trans = ~ .x
:
set.seed(123)
library(ggplot2)
ggplot(data = df)
geom_line(aes(x = date, y = v1, color = "v1"), size = 1)
geom_line(aes(x = date, y = v2, color = "v2"), size = 1)
scale_x_date(date_labels = "%d", date_breaks = "1 day")
scale_y_continuous(sec.axis = sec_axis(~ .x, name = "v2"))