Expected Input:

const d1 = 01/11/2022
const d2 = 10/11/2022

Expected Output:

I want all dates between input dates but only Mon to Fri

01/11/2022
02/11/2022
03/11/2022
04/11/2022
07/11/2022
08/11/2022
09/11/2022
10/11/2022

CodePudding user response：

Hope This simple function would help you !

function parseDate(input) {
    const parts = input.match(/(\d )/g);
    return new Date(parts[2], parts[1]-1, parts[0])
  }
  
function getDates(intialDate, finalDate) {
    const date = parseDate(intialDate)
    date.setTime(date.getTime()   24*3600000)
    const finaldate = parseDate(finalDate);
    if (finaldate.getTime() - date.getTime() > 24 * 360000000) return ['too many dates']

    const array = []

    while (finaldate.getTime()   24*36*200000 > date.getTime()) {
        array.push(date.toJSON().slice(0, 10))
        date.setTime(date.getTime()   24 * 3600000)
    }
    return array.map(elem => {
        const parts = elem.split('-')
        return [parts[2], parts[1], parts[0]].join('/')
    })
}
const d1 = '01/11/2022'
const d2 = '10/11/2022'
console.log(getDates(d1,d2))

CodePudding user response：

Can you check this solution (using moment)

import moment from "moment";
    
const isWeekend = (date) => [0, 6].includes(new Date(date).getDay());

const enumerateDaysBetweenDatesWithoutWeekend = function (startDate, endDate) {
  const dates = []

  const currDate = moment(startDate).startOf("day");
  const lastDate = moment(endDate).startOf("day");
  const firstDate = currDate.clone().format("YYYY/MM/DD")
  if (!isWeekend(firstDate)) dates.push(moment(firstDate).format("DD/MM/YYYY"));
  while (currDate.add(1, "days").diff(lastDate) < 0) {
    const date = currDate.clone().format("YYYY/MM/DD");
    if (!isWeekend(date)) dates.push(moment(date).format("DD/MM/YYYY"));
  }

  return dates;
};

const a = moment("01/11/2022", "DD/MM/YYYY");
const b = moment("10/11/2022", "DD/MM/YYYY");

console.log(...enumerateDaysBetweenDatesWithoutWeekend(a, b));