read all text files in directory and subdirectories and extract all email addresses from the textfil-CodePudding

I need to extract all email addresses from all text files within a directory with a lot of subdirectories. It is to much work to do this manually. I wrote the python script below to automate this task. However, when I execute the script I end up with an empty array printed. No errors shown. Can one please indicate what I'm doing wrong

# Import Module
import os
import re
  
# Folder Path
path = "pat to the root directory"
  
# Change the directory
os.chdir(path)

#create list and index to add the emails
new_list = []
idx = 0

# I create a method to add all email address from within the subdirectories to add 
  them to an array
def read_text_file(file_path):
    with open(file_path, 'r') as f:
        emails = re.findall(r"[a-z0-9\.\- _] @[a-z0-9\.\- _] \.[a-z] ", str(f))
        new_list.insert(idx, emails)
        idx   1
     
# iterate through all file and call the method from above
for file in os.listdir():
    # Check whether file is in text format or not
    if file.endswith(".txt"):
        p = f"{path}\{file}"
        # call read text file function
        read_text_file(p)

#print the array    
print (new_list)

CodePudding user response：

to check subdirectories as said you want, you need to check if the current item in the os.listdir() list is a folder and if so check all the file in that folder (and if there are more folders in that folder check them as well) or a file that ends with .txt

you also need to read() the file (f.read()) and only then you can pass it to re.findall()

# Import Module
import os
import re

# Folder Path
PATH = r"path to folder"  # constants are UPPER CASED LETTERS

# create list to add the emails
new_list = []


def read_text_file(file_path):
    global new_list
    with open(file_path, 'r') as f:
        emails = re.findall(r"[a-z0-9.\- _] @[a-z0-9.\- _] \.[a-z] ", str(f.read()))
        new_list  = emails


def find_all_text_files(path):
    # iterate through all file and call the method from above
    path = path if path.endswith("\\") else path   "\\"
    for file_or_dir in os.listdir(path):
        # Check whether file is in text format or not
        if os.path.isfile(path   file_or_dir) and file_or_dir.endswith(".txt"):
            file_path = path   file_or_dir
            # call read text file function
            read_text_file(file_path)
        # if the current item is dir
        elif os.path.isdir(path   file_or_dir):
            new_path = path   file_or_dir
            find_all_text_files(new_path)


def main():
    global new_list
    find_all_text_files(PATH)
    # print the array
    print(new_list)


if __name__ == '__main__':
    main()

CodePudding user response：

When your code doesn't produce expected results, you need to debug it to find the cause. Is it your regex? Is it your list.insert()? Is it the conversion of the file handle f to a string directly Something else entirely? Let's find out by modifying your read_text_file() func to print status:

def read_text_file(file_path):
    print(f"attempting to parse {file_path}")
    with open(file_path, 'r') as f:
        huge_line = f.read()
        emails = re.findall(r"[a-z0-9.\- _] @[a-z0-9.\- _] \.[a-z] ", huge_line)
        print(f"found {len(emails)} emails in file {file_path}")
        new_list.extend(emails)

I dropped the idx var and just used list.extend(). Try that out and see where it fails, then add more print statements as needed to narrow it down.