I want to filter a list of strings that includes any specific string with using list comprehension. I tried following the code, but it didn't work.

ignore_paths = ['.ipynb_checkpoints', 'New', '_calibration', 'images']
A = [x for x in lof1 if ignore_paths not in x]

but when I try with one string, it will work:

A = [x for x in lof1 if 'images' not in x]

in fact, I want to define a list of a forbidden path (or string) and check if there is a certain path that exists, then ignore that.

I can do that with normal for and if loop and check one by one, but it is not fast. I am looking for a fast way because I need to check around 150k paths.

Thanks

EDIT: To make it clear, if I had a list of files as below:

lof1 = ['User/images/20210701_151111_G1100_E53100_r121_g64_b154_WBA0_GA0_EA0_6aa87af_crop.png', 'User/images/16f48a97-7111-4f66-92cc-dc7329e7ec92.png', 'User/images/image_2022_06_21-11_41_04_AM.png']

I need to return an empty list since all of the elements contain 'images'

CodePudding user response：

Do you have duplicates? if not, you can use sets which will be very fast

allowed = set(lof1) - set(ignore_paths)

CodePudding user response：

Try:

A = [x for x in lof1 if x not in ignore_paths]