I need to make a function named f3Groups() that accepts one argument. As well as a list named cgList to represent the whole class, containing 3 lists representing the 3 groups. cgList can be an empty list but there cannot be any empty group, for example cgList = [] when there is no student in this class. Return the cgList but I have no idea how to do that. So far I have only made a function printing out list of user inputs.
def get_student_list():
stdlist = []
while True:
iStr = input('Please enter a new student name, ("quit" if no more student)')
if iStr == "quit":
return stdlist
if iStr == "":
print("Empty student name is not allowed.")
else:
stdlist.append(iStr)
stdList = get_student_list()
print("The whole class list is")
for x in stdList:
print(x, end=' ')
``
I want 7 user inputs. User input 1, 4 and 7 in one list group. User input 2 and 5 in one group. User input 3 and 6 in one group. After that print them horizontally.
``The whole class list is ['Student a', 'Student b', 'Student c', 'Student d', 'Student e'. 'Student f', 'Student g']
Group 1: ['Student a', 'Student d', 'Student g']
Group 2: ['Student b', 'Student e']
Group 3: ['Student c', 'Student f']
`
The above is the output I want. Is there a way to do it?
CodePudding user response:
here is the code you're after:
def get_student_list():
stdlist = []
while True:
iStr = input('Please enter a new student name, ("quit" if no more student)')
if iStr == "quit":
return stdlist
if iStr == "":
print("Empty student name is not allowed.")
else:
stdlist.append(iStr)
def get_group_list(stdList):
group1 = [stdList[0], stdList[3], stdList[6]]
group2 = [stdList[1], stdList[4]]
group3 = [stdList[2], stdList[5]]
grpList = [group1, group2, group3]
return grpList
stdList = get_student_list()
grpList = get_group_list(stdList)
print("The whole class list is", stdList)
for i in range(len(grpList)):
print("Group " str(i), grpList[i])
As you can see, to print a list after a string horizontally, just add a comma and then the variable after the string.
a_list = [item1, item2]
print("A list: ", a_list)
Prints:
A list: [item1, item2]
Additionally, to get the students into groups use nested lists as a simple solution. This involves lists within lists. Students can be allocated with indices.
CodePudding user response:
I want 7 user inputs.
Then you don't need a while True loop you just need to iterate until you reach 7. For that you can use a while i < 8
loop. And set i = 1
User input 1, 4 and 7 in one list group. User input 2 and 5 in one group. User input 3 and 6 in one group.
In your for loop you can use the i
variable to check which group you should place the student in.
After that print them horizontally.
Then you can just print them out individually after the function returns.
def f3Groups():
stdlist = [[],[],[]] # three groups so 3 lists
i = 1
while i < 8:
iStr = input('Please enter a new student name, ("quit" if no more student)')
if iStr == "quit":
return stdlist
if iStr == "":
print("Empty student name is not allowed.")
else:
if i in [1,4,7]:
stdlist[0].append(iStr)
elif i in [2,5]:
stdlist[1].append(iStr)
else:
stdlist[2].append(iStr)
i =1 # increase i by one when student is added.
return stdlist
stdList = f3Groups()
for i, x in enumerate(stdList):
print(f"Group {i 1}: {x}")
output
Group 1: ['Student a', 'Student d', 'Student g']
Group 2: ['Student b', 'Student e']
Group 3: ['Student c', 'Student f']
If alternatively you wanted to add a student to each list one by one so they all remain as close to the same length as possible. you could do it like this.
def get_student_list():
stdlist = []
while True:
iStr = input('Please enter a new student name, ("quit" if no more student)')
if iStr == "quit":
return stdlist
if iStr == "":
print("Empty student name is not allowed.")
else:
stdlist.append(iStr)
def f3Groups(stdlist):
groups = [[],[],[]]
for i,x in enumerate(stdlist):
if i % 3 == 0:
groups[0].append(x)
if i % 3 == 1:
groups[1].append(x)
else:
groups[2].append(x)
return groups
stdlist = get_student_list()
groups = f3Groups(stdlist)
for i, x in enumerate(stdlist):
print(f"Group {i 1}: {x}")
creates the same output as previous example.