Convert a bytearray to a integer array in Python-CodePudding

I have the following bytearray on Python

bytearray(b'\x02\xcb\x00\n\x02\xcb\x00\n\x02\xcb\x00\n\x02\xcb\x00\n\')

and I want to conver the hexa values of the bytearray to an integer array of values converting the hexa to integer: x02cb00 to integer values for each '\n'. List just separe them each one. It should look like:

[183040, 183040, ... 183040]

How can I get it?

I did a list(bytarray) and it just worked for single values not composite ones.

CodePudding user response：

You can split the bytearray on newline and then map it to integers

xs = bytearray(b'\x02\xcb\x00\n\x02\xcb\x00\n\x02\xcb\x00\n\x02\xcb\x00\n')

result = []
for line in xs.split(b'\n'):
  result.append(int.from_bytes(line))

result[:-1]

since xs.split(b'\n') return a list ending with bytearry(b'') you should drop the last element.

CodePudding user response：

Try:

b = bytearray(b'\x02\xcb\x00\n\x02\xcb\x00\n\x02\xcb\x00\n\x02\xcb\x00\n')
int_list = [int.from_bytes(n, "big", signed=False) for n in b.split(b'\n')[:-1]]
print(int_list)

Output:

[183040, 183040, 183040, 183040]

Just be careful about the endianess ["big", "little"] and the sign.