This is my Python code:

class Holiday:
    def __init__(self, month, day, hours):
        self.month = month
        self.day = day
        self.hours = hours

    def __str__(self):
        return f'Month = {self.month}, Day = {self.day}, Hours = {self.hours}'


list_of_holidays = []

with open("Holidays.txt") as afile:
    for line in afile.readlines()[1:]:
        list_of_holidays.append(Holiday(*map(str.strip, line.split("/"))))

This is the output:

Month = 1, Day = 6, Hours = 10-18

Month = 4, Day = 15, Hours = 10-18

Month = 4, Day = 17, Hours = 10-18

Holidays.txt has the format: month / day / hours

I want to be able to do something like this:

day_input = 6

month_input = 1

if month and day in list_of_holidays:

print(Hours)


-> and have Hours be the corresponding Hours on the same row.I simply can't get this to work how I want it and there's definitely something I'm missing in the code

I simply can't get this to work how I want it and there's definitely something I'm missing in the code.

Is there a way to do this and compare the inputs directly to the list and getting the corresponding Hours?

CodePudding user response：

How you define each instance of Holiday isn't really relevant, so the solution is the same whether or not you used *map(...) to provide the arguments to Holiday.

You just need to check the given month and day against each holiday.

for holiday in list_of_holidays:
    if month_input == holiday.month and day_input == holiday.day:
        print(holiday.hours)
        break  # If you know there won't be more than one such holiday