how can I add a new value and delete the old one from a .innerText-CodePudding

I'm starting to study programming and I am trying to make a calculator with html css js with my learning so far. But I got stuck in one part: my calculator shows the value typed in currentvalue.innerText and when it receives an operation, the value appears on top of it, in previousvalue.innerText, I wanted the currentvalue to be reset only when the person inserts a new number, then I could extract the new value in a variable called num2 and use it to do the math

this is the part of the function that I am talking about:

function insert(value){        
    
    if (value === '/'|| value ==='*'|| value === '-'|| value === ' '){
        
        previousOperation.innerText = currentOperation.textContent   ` ${value}`;
        num1 = previousOperation.innerText.slice(0, -2);
        
        op = value;

        return
    }
    
    if(value === '.') {    
        currentOperation.innerText  = '.'; // O '0' inicial permanece e é adicionado um ponto
    } else if (currentOperation.innerText === '0'){ // Exclui o 0 inicial e adiciona o value digitado direto
        currentOperation.innerText = value;
    } else {
        currentOperation.innerText  = value;
    } 
}

I tried resetting the currentvalue.innerText, but only when the previoustvalue.innerText already had a value, but doing that it only shows one number at a time in my currentvalue.innerText, it doesn't save the value and show all the others typed

CodePudding user response：

You must convert 'currentOperation.innerText' and 'value' to numbers before applying the formula.

if(value === '.') {    
    currentOperation.innerText  = '.'; // O '0' inicial permanece e é adicionado um ponto
} else if (currentOperation.innerText === '0'){ // Exclui o 0 inicial e adiciona o value digitado direto
    currentOperation.innerText = value;
} else {
    const previousNumber = parseInt(currentOperation.innerText)
    const currentNumber = parseInt(value);

    currentOperation.innerText = `${previousNumber   currentNumber}`;
}