I have the following situation:
def func1(a = 0, b = 0):
return a b**2
def func2(x):
if x == 'a':
return func1(a = 2)
elif x == 'b':
return func2(b = 2)
print(func2('a'))
Is there a way to just pass a
not as a String and get rid of the if statements?
CodePudding user response:
Construct a dict and use that with the mapping unpacking syntax.
def func2(x):
return func1(**{x: 2})
You might still want an if
statement to verify that the value of x
is the name of a valid parameter to func1
. As shown here, a call like func2('c')
will produce a TypeError
when attempting to call func1
using {'c': 2}
.