How to find smallest element of array V(12,9) and its number?
Private Sub Command2_Click()
Dim V(1 To 12, 1 To 9) As Integer
Randomize
For i = 1 To 12
For j = 1 To 9
V(i, j) = Rnd * 50
Next j
Next i
CodePudding user response:
Identify the Minimum Value in a 2D Array
- See the information and results in the Immediate window (Ctrl G). It's nicer and more educational than the presentation in the message box.
- With such small numbers you could replace all the Longs with Integers if that is a requirement. Here is a link describing why we mostly don't use Integer anymore.
Private Sub Command2_Click()
Const Max As Long = 50
' Populate the array.
Dim V(1 To 12, 1 To 9) As Long
Dim i As Long
Dim j As Long
Randomize
For i = 1 To 12
For j = 1 To 9
V(i, j) = Rnd * Max
Next j
Next i
Debug.Print GetDataString(V, , , "Random numbers from 0 to " & Max)
Debug.Print "How Min Was Changed in the Loop (It Started at " & Max & ")"
Debug.Print "The array was looped by rows."
Debug.Print "Visually find the following values to understand what happened."
Debug.Print "i", "j", "Min"
' Calculate the minimum.
Dim Min As Long: Min = Max
For i = 1 To 12
For j = 1 To 9
If V(i, j) < Min Then
Min = V(i, j)
Debug.Print i, j, Min
End If
Next j
Next i
Debug.Print "The minimum is " & Min & "."
MsgBox GetDataString(V, , , "Random numbers from 0 to " & Max) & vbLf _
& "The minimum is " & Min & ".", vbInformation
End Sub
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
' Purpose: Returns the values of a 2D array in a string.
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''
Function GetDataString( _
ByVal Data As Variant, _
Optional ByVal RowDelimiter As String = vbLf, _
Optional ByVal ColumnDelimiter As String = " ", _
Optional ByVal Title As String = "PrintData Result") _
As String
' Store the limits in variables
Dim rLo As Long: rLo = LBound(Data, 1)
Dim rHi As Long: rHi = UBound(Data, 1)
Dim cLo As Long: cLo = LBound(Data, 2)
Dim cHi As Long: cHi = UBound(Data, 2)
' Define the arrays.
Dim cLens() As Long: ReDim cLens(rLo To rHi)
Dim strData() As String: ReDim strData(rLo To rHi, cLo To cHi)
' For each column ('c'), store strings of the same length ('cLen')
' in the string array ('strData').
Dim r As Long, c As Long
Dim cLen As Long
For c = cLo To cHi
' Calculate the current column's maximum length ('cLen').
cLen = 0
For r = rLo To rHi
strData(r, c) = CStr(Data(r, c))
cLens(r) = Len(strData(r, c))
If cLens(r) > cLen Then cLen = cLens(r)
Next r
' Store strings of the same length in the current column
' of the string array.
If c = cHi Then ' last row (no column delimiter ('ColumnDelimiter'))
For r = rLo To rHi
strData(r, c) = Space(cLen - cLens(r)) & strData(r, c)
Next r
Else ' all but the last row
For r = rLo To rHi
strData(r, c) = Space(cLen - cLens(r)) & strData(r, c) _
& ColumnDelimiter
Next r
End If
Next c
' Write the title to the print string ('PrintString').
Dim PrintString As String: PrintString = Title
' Append the data from the string array to the print string.
For r = rLo To rHi
PrintString = PrintString & RowDelimiter
For c = cLo To cHi
PrintString = PrintString & strData(r, c)
Next c
Next r
' Assign print string as the result.
GetDataString = PrintString
End Function
CodePudding user response:
First you need to declare the data type of variables i and j
Dim i, j as Integer
second, your array name V not A so correct this line
V(i, j) = Rnd * 50
finally, if your array contains numbers you can use this line
Debug.Print WorksheetFunction.Min(V)