Make a comparison and print out what is not in the list, how can I do that?-CodePudding

import re


Hosts = ["gvff", "etc"]



def list():
    with open('C:/Users/user/Desktop/scripts/devices.txt', 'r') as file:
        for row in file:
            device = row.rsplit('\n')
            devices = re.search("^(.*?)\,(.*?)\,(.*?)\,", device[0])
            if devices != None:
                device = devices.group(1)
                hardwaretype = devices.group(2)
                level = devices.group(3)
                
                for host in Hosts:
                    if device.startswith(host):
                        if level == 'Production' or level == 'Production-Secondary':
                            print(f'| {device} | {hardwaretype} | {level} |')



list()

Hey I'm not getting anywhere at the moment. I want to compare the hosts list with the devices.txt. It currently prints me everything it has matched, but I need the items that could not be matched. How could I do that here?

Current Output: | blabla.bla.bla | physical | Production | this host is in the device.txt and in the Hosts list, so its the matching output

Excepted Output: looks like above, but only the hosts which are in devices.txt but not in Hosts List.

Many greetings

CodePudding user response：

Just add the not keyword before device.startswith(host), it will make the condition true if the device not starts with 'host' otherwise false.

change

if device.startswith(host):
   ...

if not device.startswith(host):
   ...

CodePudding user response：

example host in device.txt: blabla.blabla.blabla, physical, Production