How to use a variable defined in two nested for loops as stopargument for the thrid loop-CodePudding

I have three loops for example that contain the code

for i in $words
do
height=$((20   (10 * i)))
done

for j in {0..3}
do
x=$((10   (15 * j)))
done

for k in $height
do 
y=$((110 - k)/2))
done

With $words containing the numbers

0 3 4 5

height will give

x will give

and y should give

But the problem is that height is defined in one of the for loops so I can't use it as an argument for the last for loop. The table of height is also vertical and not horizontal. When I do a nested for loop I get too many rows.

My desired output should look like this using echo please for example

echo "<$height> <$x> <$y>

and it should look like this

20   1O   40
50   25   30
60   40   25
70   55   20

Thank you

CodePudding user response：

If you don't want to nest loops and every loop will iterate the same number of times, you can use arrays to keep track of their values.

#!/bin/bash
# Create arrays to store each value
h_values=()
x_values=()
y_values=()
words="0 3 4 5"

for i in $words
do
# append an array with a calculated value
h_values =( "$((20   (10 * i)))" )
done

for j in {0..3}
do
x_values =( "$((10   (15 * j)))" )
done

# this loops over each element of h_values, the heights we calculated before
for k in "${h_values[@]}"
do 
y_values =( "$(((110 - k)/2))" )
done

# C-style for loop to print the i-th index of each array in order
for ((i=0 ; i < ${#h_values[@]} ; i  )) ; do
  printf '%s %s %s\n' "${h_values[i]}" "${x_values[i]}" "${y_values[i]}"
done

With your word values I get this output:

Which doesn't quite match your expected output but is pretty close. Maybe the math is a little off somewhere.