Tomcat Spring can not realize the path of the file even the path has been added to servlet.xml and H-CodePudding

I am newbie with Java Spring and making a very simple program with Spring.

I decided to put my web.xml, demo-config.servet.xml and some folders and xml files into one path to make it to be clear.

Then, I updated the HomeController.java file :

package DemoSpringMVC.Controller;
import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
@Controller
public class HomeController {
@RequestMapping("/")
public String Index() {
    return "user/index";
}
}

and I updated the demo-config-servlet.xml file

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans 
http://www.springframework.org/schema/beans/spring-beans.xsd
    http://www.springframework.org/schema/context 
http://www.springframework.org/schema/context/spring-context-4.3.xsd">
<context:component-scan
    base-package="DemoSpringMVC"></context:component-scan>
    <bean >
        <property name="prefix" value="/WEB-INF/views/"></property>
        <property name="suffix" value=".jsp"></property>
    </bean>
    </beans>

The eclipse shows no error, so I thought that I have no error.

But when I ran my DemoSpringMVC, it show me that the link is inactive ? As you can see in this picture ?

Here is my code, if you need to reference

https://github.com/nguyencuc2586/Spring3.1

Could you please give me some advices ? Thank you in advance.

CodePudding user response：

The code is ok. maybe It may be your tomcat configuration problem

CodePudding user response：

As per your code you are using servlet API 4.0 which needs Tomcat 9.0 and you mentioned that you are using Tomcat 10, so try using the Tomcat 9.0 version.