regex for matching all characters in the string any where-CodePudding

I need a regex for matching all characters in the string. But it is not matter where that characters.

EG - Input array - [a, b, c] Following words should match

abc
axbxc
cybxbxca

But should not match following. Because these words has not all input charters.

axbxyz
bxba

CodePudding user response：

You can use Array.prototype.every() with String.prototype.includes() to filter the matching words:

const inputArray = ['a', 'b', 'c'];

const words = [
  // PASS:
  'abc',
  'axbxc',
  'cybxbxca',

  // FAIL:
  'axbxyz',
  'bxba',
];

const result = words.filter(word => inputArray.every(str => word.includes(str)));
console.log(result); // ["abc", "axbxc", "cybxbxca"]

CodePudding user response：

You need a regexp like ^(?=.*a)(?=.*b)..., which you can build dynamically from the input:

const inputArray = ['a', 'b', 'c'];

let re = RegExp('^'   inputArray.map(x => '(?=.*'   x   ')').join(''))

const words = [
    'abc',
    'axbxc',
    'cybxbxca',
    'axbxyz',
    'bxba',
];

console.log(words.map(w => [w, re.test(w)]))

If the input can contain regex special symbols, don't forget to escape them properly.