regex for ignoring character if inside () parenthesis?-CodePudding

I was doing some regex, but I get this bug:

I have this string for example " 1/(1/10) (1/30) 1/50" and I used this regex /\ .[^\ ]*/g
and it working fine since it gives me [' 1/(1/10)', ' (1/30)', ' 1/50']

BUT the real problem is when the is inside the parenthesis ()

like this: " 1/(1 10) (1/30) 1/50"

because it will give [' 1/(1', ' 10)', ' (1/30)', ' 1/50']

which isn't what I want :(... the thing I want is [' 1/(1 10)', ' (1/30)', ' 1/50']
so the regex if it see \(.*\) skip it like it wasn't there...

how to ignore in regex?

my code (js):

const tests = {
      correct: "1/(1/10) (1/30) 1/50",
      wrong  : "1/(1 10) (1/30) 1/50"
}

function getAdditionArray(string) {
      const REGEX = /\ .[^\ ]*/g; // change this to ignore the () even if they have the   sign
      const firstChar = string[0];

      if (firstChar !== "-") string = " "   string;

      return string.match(REGEX);
}

console.log(
    getAdditionArray(test.correct),
    getAdditionArray(test.wrong),
)

CodePudding user response：

You can exclude matching parenthesis, and then optionally match (...)

\ [^ ()]*(?:\([^()]*\))?

The pattern matches:

\ Match a
[^ ()]* Match optional chars other than ( )
(?: Non capture group to match as a whole part
- \([^()]*\) Match from (...)
)? Close the non capture group and make it optional

See a regex101 demo.

Another option could be to be more specific about the digits and the and / and use a character class to list the allowed characters.

\ (?:\d [ /])?(?:\(\d [/ ]\d \)|\d )

See another regex101 demo.