#nested dictionary
card_values = {
"normal": [2, 3, 4, 5, 6, 7, 8, 9, 10],
"suited": {"J":10, "Q":10, "K":10, "A":11}
}
#code I wrote to try and iterate over the values
all_cards = []
for i in card_values:
for j in card_values[i]:
all_cards.append(j)
print(all_cards)
#output needed
all_cards = [2, 3, 4, 5, 6, 7, 8, 9, 10, 11]
CodePudding user response:
You can use this snippet:
all_cards = card_values["normal"] list(card_values["suited"].values())
this returns :
[2, 3, 4, 5, 6, 7, 8, 9, 10, 11]
what each part of the code is doing:
We are first getting [2, 3, 4, 5, 6, 7, 8, 9, 10]
from the "normal"
key in card_values
. Then we are getting only the values from the "suited"
key in card_values
and then converting them to a list which leaves
CodePudding user response:
I would make a set to get the unique values and then sort it.
card_values = {
"normal": [2, 3, 4, 5, 6, 7, 8, 9, 10],
"suited": {"J":10, "Q":10, "K":10, "A":11}
}
all_cards = sorted(
set(card_values["normal"])
| set(card_values["suited"].values())
)
print(all_cards)