I used python netdiscover
tool to obtain which devices are connected to my local network, and I want to write their IP addresses into a text file. To do this, I want to take out IP addresses from the following list which is the product of netdiscover
:
lst = [{'ip': b'192.168.1.1', 'mac': b'40:35:c1:8e:7e:78'},
{'ip': b'192.168.1.108', 'mac': b'44:a0:50:56:22:99'},
{'ip': b'192.168.1.101', 'mac': b'ff:5b:4b:46:70:67'},
{'ip': b'192.168.1.100', 'mac': b'6a:ef:3b:58:8f:f0'},
{'ip': b'192.168.1.102', 'mac': b'46:72:b0:ef:3c:a8'},
{'ip': b'192.168.1.104', 'mac': b'58:c2:f5:b1:65:42'}]
The IP addresses are bytes
object. To convert them to a string so that I can write them to a file, I used the following code:
for i in lst:
f=i.get("ip")
f1=str(f)
f2=f1.partition("b")
print(f2[2])
This code gave me what I desire, but it seems ridiculous to me. Is there a more elegant way to take out the IP addresses from list?
CodePudding user response:
With simple list comprehension and bytes.decode
function:
ips = [d['ip'].decode() for d in lst]
print(ips)
['192.168.1.1', '192.168.1.108', '192.168.1.101', '192.168.1.100', '192.168.1.102', '192.168.1.104']
CodePudding user response:
You can use this .Hope it helpes.. [1]: https://i.stack.imgur.com/ggOQ7.png