Time difference between datetime and timedelta for python-CodePudding

I want to find the seconds difference between a datetime variable and a timedelta variable.

So my endtime variable is in timedelta format but the relevant information is 09:59:06.374829103

My starttime variable is in datetime format and the relevant information is 9:58

I want to find the difference between these two

df['endTime'][0]:
output: Timedelta('0 days 09:59:06.374829103')

df['startTime'][0]
output: datetime.datetime(2023, 1, 6, 9, 58)

I want how many seconds for:

(df['endTime'][0] - df['startTime'][0]) seconds

CodePudding user response：

You can use dt accessor to convert DatetimeIndex in total_seconds:

# dt - dt.normalize() remove the date part and keep only time
>>> df['endTime'].dt.total_seconds() - \
        df['startTime'].sub(df['startTime'].dt.normalize()).dt.total_seconds()

0    66.374829
dtype: float64

Input data:

>>> df
                    endTime           startTime
0 0 days 09:59:06.374829103 2023-01-06 09:58:00

>>> df.dtypes
endTime      timedelta64[ns]
startTime     datetime64[ns]
dtype: object