There's this code right here:
thing = "Stuff.\nHello!"
result = thing.split(" ")
# ^Is equal to ["Stuff.", "Hello!"] despite the delimiter being a single space instead of a newline
How do I make it so that the newline is included, making the result var equal to ["Stuff.\n", "Hello!"] instead?
I'm using Ruby 1.9.2. For those who are curious, I need to know this for the sake of a word-wrapping algorithm that replaces line-break tags with newlines.
CodePudding user response:
You can use a regexp with a positive look-behind assertion:
thing = "Stuff.\nHello!"
thing.split(/(?<=\s)/)
#=> ["Stuff.\n", "Hello!"]
The positive look-behind assertion (?<=pat)
ensures that the preceding characters match pat
, but doesn’t include those characters in the matched text.
CodePudding user response:
One could simply use String#lines.
"Stuff.\nHello!".lines #=> ["Stuff.\n", "Hello!"]
"Stuff.\nHello!\n".lines #=> ["Stuff.\n", "Hello!\n"]