How to get unique values in nested list along single column?-CodePudding

I need to extract only unique sublists based on first element from a nested list. For e.g.

in = [['a','b'], ['a','d'], ['e','f'], ['g','h'], ['e','i']]
out = [['a','b'], ['e','f'], ['g','h']]

My method is two break list into two lists and check for elements individually.

lis = [['a','b'], ['a','d'], ['e','f'], ['g','h']]
lisa = []
lisb = []
for i in lis:
    if i[0] not in lisa:
        lisa.append(i[0])
        lisb.append(i[1])
out = []
for i in range(len(lisa)):
    temp = [lisa[i],lisb[i]]
    out.append(temp)

This is an expensive operation when dealing with list with 10,00,000 sublists. Is there a better method?

CodePudding user response：

Use memory-efficient generator function with an auziliary set object to filter items on the first unique subelement (take first unique):

def gen_take_first(s):
    seen = set()
    for sub_l in s:
        if sub_l[0] not in seen:
            seen.add(sub_l[0])
            yield sub_l

inp = [['a','b'], ['a','d'], ['e','f'], ['g','h'], ['e','i']]
out = list(gen_take_first(inp))
print(out)

[['a', 'b'], ['e', 'f'], ['g', 'h']]