I'm working with a JSON object having the following structure:
{
"key-foo-1.0": [
{
"key1": "foo",
"key2": "bar",
"id": "01"
},
{
"key1": "foo",
"key2": "bar",
"id": "23"
}
],
"key-bar-1.0": [
{
"key1": "foo",
"key2": "bar",
"id": "45"
},
{
"key1": "foo",
"key2": "bar",
"id": "67"
}
],
"key-baz-1.0": [
{
"key1": "foo",
"key2": "bar",
"id": "89"
}
]
}
I want to get all the id
values where the "parent" key name matches the pattern .*foo.*
or `.bar..
So in my example something like this:
cat json | jq <some filter>
01
23
45
67
Based on https://unix.stackexchange.com/questions/443884/match-keys-with-regex-in-jq I tried:
$ cat json | jq 'with_entries(if (.key|test(".*foo.*$")) then ( {key: .key, value: .value } ) else empty end )'
{
"key-foo-1.0": [
{
"key1": "foo",
"key2": "bar",
"id": "01"
},
{
"key1": "foo",
"key2": "bar",
"id": "23"
}
]
}
But I don't really know how to continue.
I also think there is a better/simpler solution.
CodePudding user response:
You could go with:
jq -r '.[keys_unsorted[] | select(test(".*foo.*|.bar.."))][].id'
01
23
45
67
This gathers all keys using keys_unsorted
, then select
s those matching the regular expression in test
. The wrapping .[…]
descends into them, the following []
iterates over the children, and .id
outputs the values as raw text using the -r
flag.
CodePudding user response:
you can use the following JQ expression:
jq 'to_entries[] | select(.key | test(".*foo.*|.*bar.*")) | .value[] | .id'