I can't print the first index of the Character Array?-CodePudding

#include <stdio.h>
#include <stdlib.h>

int main()
{
    char A[100];
    char c;
    scanf("%s", &A);
    while ((getchar()) != '\n');
    scanf("%c", &c);
    int i, count = 0;
    for(A[i] = 0; A[i] != c; i  ) {
        count  ;
    }
    //printf("%d",count);
    for(i = 0; i < count; i  ) {
        printf("%c", A[i]);
    }
    return 0;
}

I want to print (ca) if I enter input String A as (cat) and character c as (t ).But I am getting output as (a) the first word is not printing .Please tell me what is wrong with my code.

CodePudding user response：

for(A[i] = 0; A[i] != c; i  )

This assigns 0 to the first position in A (A[i] = 0). You probably wanted to write

for(i = 0; A[i] != c; i  )

instead.

There are some other problems with the code as well, especially in error handling, but I'll let you figure those out.

CodePudding user response：

Well, what does the compiler say? Assuming your program is stored in test.c:

$ gcc -Wall test.c
test.c: In function ‘main’:
test.c:8:13: warning: format ‘%s’ expects argument of type ‘char *’, but argument 2 has type ‘char (*)[100]’ [-Wformat=]
    8 |     scanf("%s", &A);
      |            ~^   ~~
      |             |   |
      |             |   char (*)[100]
      |             char *
test.c:12:14: warning: ‘i’ is used uninitialized in this function [-Wuninitialized]
   12 |     for(A[i] = 0; A[i] != c; i  ) {
      |         ~~~~~^~~