Int main ()
{
double sum=0;
Double the item;
int i,n;
The scanf (" % d ", & amp; N);
for(i=1; i<=n; I +=2)
{
The item (I + 1)=I * * (I + 2);
The sum +=item;
}
Printf (" % ld ", sum);
return 0;
}
CodePudding user response:
Why ask not to come out???CodePudding user response:
Program, calculate the following sequence first n and an odd number of items in the series in the form of: 3 + 1 * 2 * 2 * 3 * 4 + 5 + 3 * 4 *... + n * (n + 1) * (n + 2) +... , prompt accumulativeEnter
Only a set of data input, on one line from the keyboard input the value of n (n<100),
The output
CodePudding user response:
Try thisfor(i=1; i<=n; i++)
CodePudding user response:
#includeInt main ()
{
Int sum;
Int item=0;
Int I, b=0, n.
The scanf (" % d ", & amp; N);
for(i=1; i<=n; I +=2)
{
B=b + item;
The item (I + 1)=I * * (I + 2);
Sum=item + b;
}
Printf (" % ld ", sum);
return 0;
}