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Table for help: there is a word, the word library, therefore, how to measure words in the table the

Time:11-15

Existing materials:
Article 1. A thesaurus: 700000 (the number of words each word is not necessarily the same, ranging from two to six words)
2. The word frequency table a: word library were analyzed, and it is concluded that the capacity of 4000 word list, attached the corresponding word frequency,
Requirements:
1. The word table (level), commonly used the word table condition that covers 80% of the words in a thesaurus (full cover, that is, within the term of each word to cover),
2. Get 3 tables (secondary word table), on condition that covers 50% of the words in a thesaurus (whole),


I don't know the problem hair which plate, burke,

CodePudding user response:

Look for the sort of artificial intelligence BBS ask, relational database to deal with this logic, profession is not wrong,

CodePudding user response:

Thank you for your reply, have recommended the BBS of "artificial intelligence"? Do not know how to start.
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