javascript replace letters from array 1 with number from array 2 and calculate the sum of these numb-CodePudding

I have two array

array number 1:

let search  = ['ا', 'ب', 'ج', 'د', 'ه','و', 'ز', 'ح', 'ط', 'ي','ك', 'ل', 'م', 'ن', 'س','ع', 'ف', 'ص', 'ق', 'ر','ش', 'ت', 'ث', 'خ', 'ذ','ظ', 'ض', 'غ'];

array number 2:

let replace = ['1', '2', '3', '4', '5','6', '7', '8', '9', '10','20', '30', '40', '50', '60','70', '80', '90', '100', '200','300', '400', '500', '600', '700','800', '900', '1000'];

and this is an input :

let word = "محمد";

I want in javascript search the letters of the variable word and replace them with the equivalent of number in the replace array .The replace array and the search array have the same numbers of letters and number.

The output will be:

م 40
ح 8
م 40
د 4

total = 92

let word = "محمد";
let search = ['ا', 'ب', 'ج', 'د', 'ه', 'و', 'ز', 'ح', 'ط', 'ي', 'ك', 'ل', 'م', 'ن', 'س', 'ع', 'ف', 'ص', 'ق', 'ر', 'ش', 'ت', 'ث', 'خ', 'ذ', 'ظ', 'ض', 'غ'];
let replace = ['1', '2', '3', '4', '5', '6', '7', '8', '9', '10', '20', '30', '40', '50', '60', '70', '80', '90', '100', '200', '300', '400', '500', '600', '700', '800', '900', '1000'];
if (word === "") {
  document.write('the field is empty');
} else {
  w = word.split("").filter(function(ele) {
    return ele.replace(search, replace);
  }).map(function(ele) {
    return ele   ele;
  });
}
console.log(w);

CodePudding user response：

Assuming you meant the expected result was 92, you can do this by forst splitting the input, then finding the index of the item in find and aggregating the result using reduce finding the value from replace

let search  = ['ا', 'ب', 'ج', 'د', 'ه','و', 'ز', 'ح', 'ط', 'ي','ك', 'ل', 'م', 'ن', 'س','ع', 'ف', 'ص', 'ق', 'ر','ش', 'ت', 'ث', 'خ', 'ذ','ظ', 'ض', 'غ'];
let replace = ['1', '2', '3', '4', '5','6', '7', '8', '9', '10','20', '30', '40', '50', '60','70', '80', '90', '100', '200','300', '400', '500', '600', '700','800', '900', '1000'];

let word = "محمد";

let result = word.split("")
                .map(x => search.indexOf(x))
                .reduce( (acc,i) => acc   parseInt(replace[i],10),0);
console.log(result);

You could impove this by storing integers in your replace array which would negate the need for parseInt

CodePudding user response：

I would suggest creating a map for the two arrays:

let word = "محمد";
let search = ['ا', 'ب', 'ج', 'د', 'ه', 'و', 'ز', 'ح', 'ط', 'ي', 'ك', 'ل', 'م', 'ن', 'س', 'ع', 'ف', 'ص', 'ق', 'ر', 'ش', 'ت', 'ث', 'خ', 'ذ', 'ظ', 'ض', 'غ'];
let replace = ['1', '2', '3', '4', '5', '6', '7', '8', '9', '10', '20', '30', '40', '50', '60', '70', '80', '90', '100', '200', '300', '400', '500', '600', '700', '800', '900', '1000'];

let map = Object.fromEntries(search.map((letter, i) => [letter, replace[i]]));

let w = Array.from(word, letter => map[letter]).filter(Boolean);
console.log(w);
// If you want to have a concatenated string:
console.log(w.join(","));
// Or a sum:
console.log(w.reduce((a, b) => a    b, 0));

Note: If your intention is to sum, or make other numerical calculations, I would suggest to make the replace array an array of numbers, not strings.

CodePudding user response：

Here is one way to replace the letters with numbers and output the total.

let word = "محمد";
let search = ['ا', 'ب', 'ج', 'د', 'ه', 'و', 'ز', 'ح', 'ط', 'ي', 'ك', 'ل', 'م', 'ن', 'س', 'ع', 'ف', 'ص', 'ق', 'ر', 'ش', 'ت', 'ث', 'خ', 'ذ', 'ظ', 'ض', 'غ'];
let replace = ['1', '2', '3', '4', '5', '6', '7', '8', '9', '10', '20', '30', '40', '50', '60', '70', '80', '90', '100', '200', '300', '400', '500', '600', '700', '800', '900', '1000'];
if (word === "") {
  document.write('the field is empty');
} else {
  w = word.split("").map(function(ele) {
    return ele.replace(ele, replace[search.indexOf(ele)]);
  }).reduce((acc, next)=> acc parseInt(next), 0)
}
console.log(w);

CodePudding user response：

I think you want to get abjad numbers. so if you want to get 92, you can use blow code.

let word = "محمد";
let search = ['ا', 'ب', 'ج', 'د', 'ه', 'و', 'ز', 'ح', 'ط', 'ي', 'ك', 'ل', 'م', 'ن', 'س', 'ع', 'ف', 'ص', 'ق', 'ر', 'ش', 'ت', 'ث', 'خ', 'ذ', 'ظ', 'ض', 'غ'];
let replace = ['1', '2', '3', '4', '5', '6', '7', '8', '9', '10', '20', '30', '40', '50', '60', '70', '80', '90', '100', '200', '300', '400', '500', '600', '700', '800', '900', '1000'];
if (word === "") {
  document.write('the field is empty');
} else {
  const chars = word.split('')
  var sum = 0
  chars.forEach(x => {
    const index = search.indexOf(x)
    sum  =  replace[index]
  })
}
console.log(sum);

CodePudding user response：

Logic

Split the word into letters
Find the index of each word from search.
Find the value of the above index from replace array.
Add this in a loop

Working Fiddle

let word = "محمد";
let search = ['ا', 'ب', 'ج', 'د', 'ه', 'و', 'ز', 'ح', 'ط', 'ي', 'ك', 'ل', 'م', 'ن', 'س', 'ع', 'ف', 'ص', 'ق', 'ر', 'ش', 'ت', 'ث', 'خ', 'ذ', 'ظ', 'ض', 'غ'];
let replace = ['1', '2', '3', '4', '5', '6', '7', '8', '9', '10', '20', '30', '40', '50', '60', '70', '80', '90', '100', '200', '300', '400', '500', '600', '700', '800', '900', '1000'];
let sum = 0;
word.split("").forEach(letter => {
  const index = replace[search.indexOf(letter)];
  console.log(`${index} ${letter}`)
  sum  =  index;
});
console.log(`total = ${sum}`)

CodePudding user response：

mine...

const 
  val = 
    [ 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 20, 30, 40, 50
    , 60, 70, 80, 90, 100, 200, 300, 400, 500, 600
    , 700, 800, 900, 1000 ]
, ref = "ابجدهوزحطيكلمنسعفصقرشتثخذظضغ"
  ;
function count (word)
  {
  c = 0
  for(let l of word) c  = val[ref.indexOf(l)]
  return c
  }
  
console.log( count( "محمد") ) // 92

CodePudding user response：

In case you want a reusable solution:

const word = 'محمد';
const search = ['ا', 'ب', 'ج', 'د', 'ه','و', 'ز', 'ح', 'ط', 'ي','ك', 'ل', 'م', 'ن', 'س','ع', 'ف', 'ص', 'ق', 'ر','ش', 'ت', 'ث', 'خ', 'ذ','ظ', 'ض', 'غ'];
const replace = ['1', '2', '3', '4', '5','6', '7', '8', '9', '10','20', '30', '40', '50', '60','70', '80', '90', '100', '200','300', '400', '500', '600', '700','800', '900', '1000'];;

const sumOfChars = (chars, replacements) => stringValue => {
  return stringValue.split('').reduce(
    (sum, char) => {
      const match = chars.indexOf(char);
      return match > -1 ? sum   Number(replacements[match]) : sum;
    },
    0
  );
}

console.log('charSumOfValues:', sumOfChars(search, replace)(word));

Or in two distinct functions:

const word = 'محمد';
const search = ['ا', 'ب', 'ج', 'د', 'ه','و', 'ز', 'ح', 'ط', 'ي','ك', 'ل', 'م', 'ن', 'س','ع', 'ف', 'ص', 'ق', 'ر','ش', 'ت', 'ث', 'خ', 'ذ','ظ', 'ض', 'غ'];
const replace = ['1', '2', '3', '4', '5','6', '7', '8', '9', '10','20', '30', '40', '50', '60','70', '80', '90', '100', '200','300', '400', '500', '600', '700','800', '900', '1000'];;


// --- distinct utilities
const charValues = (chars, replacements) => stringValue => {
  return stringValue.split('').map(char => {
    const match = chars.indexOf(char);
    return match > -1 ? Number(replacements[match]) : 0;
  });
};

const sum = (chars) => chars.reduce((a, b) => a   b, 0);


const getCVs = charValues(search, replace);

console.log('values:', getCVs(word));
console.log('sum:', sum(getCVs(word)));