New to C, having trouble passing pointers. I am trying to pass this 2D array of pointers which points to strings (char[]s). I keep getting the error that I can't use %s because in the function call I declare the parameter as a char. However if I use %c I only print the first three characters of 'H' 'e' 'l' and then I get a segmentation fault.
Error Code:
format specifies type 'char *' but the argument has type 'char' [-Wformat]
printf("%s ", in[i][j]);
~~ ^~~~~~~~
%c
Suggestions?
void printArray(char *in[]){
int i;
int j;
for (i = 0; i < 3; i ){
for (j = 0; j < 3; j ){
printf("%c ", in[i][j]);
}
}
main(){
char *arr1[3][3];
arr1[0][0] ="Hello";
arr1[0][1] = "World";
arr1[0][2] = "Today";
arr1[1][0] = "Is";
arr1[1][1] = "September";
arr1[1][2] = "28";
arr1[2][0] = "th";
arr1[2][1] = "2021";
arr1[2][2] = "yay";
char *j = arr1[0][0];
int k;
int p;
printf("Before: \n");
printArray(&j);
To reiterate, the goal is send the array of strings and then print them in the function "printArray"
Sorry if this is an easy question, again very new to C
Thank you
CodePudding user response:
Use variable length arrays (VLAs). They were added to C exactly for this purpose:
void printArray(int n, int m, char *in[n][m]){
for (int i = 0; i < n; i ){
for (int j = 0; j < m; j ){
printf("%s ", in[i][j]);
}
}
}
int main() {
char *arr1[3][3];
... initialize arr1
printArray(3, 3, arr1);
}
EDIT
As stated in the comment the size expression in [n]
could be omitted as it is ignored by the compiler. Though it is still useful for self-documenting. The alternative declaration could be:
void printArray(int n, int m, char *in[static n][m])
The keyword static
instructs the compiler that at least first n
elements of pointed by in
are valid.
CodePudding user response:
change
printArray(char *in[])
to
printArray(const char * in[][3])
and
printArray(&j)
to
printArray(arr1)
Then, you should be able to use %s
.
You're passing a 1D array and wanting to use it as 2D in printing.