The program is running but when I enter 9 digit error starting with 0, it's giving me an error that its invalid but I want print it as not used character. Its java basic learning, thanks for helping in advance. My whole code is running perfect and if I enter 9 digit starting with 8 then its working properly for 0, its giving me error.
import java.util.Scanner;
public class FirstDigitSIN
{
public static void main(String[] args)
{
Scanner kb = new Scanner(System.in);
System.out.print("Enter a SIN number :" );
if(kb.hasNextInt()){
// code that you want executed if the input is an integer goes in here
int num = kb.nextInt();
int numCopy = num;
int digit =0;
int count = 0;
while(num != 0 ){
num = num/10;
count ;}
if(count != 9){
System.out.println("Invalid Entry"); }
else{
System.out.println( num );
while(numCopy>0){
digit = numCopy %10;
numCopy = numCopy/10;
}if (digit == 1){
System.out.println(" Registered in Atlantic Canada ");
}else if(digit == 2){
System.out.println(" Registered in Quebec ") ;
}else if (digit == 3){
System.out.println(" Registered in Quebec ");}
else if (digit == 4){
System.out.println(" Registered in Ontario ");}
else if (digit == 5){
System.out.println(" Registered in Ontario ");}
else if (digit == 6){
System.out.println(" Registered in Prairie Provinces, NWT, Nunavut, Northwest Ontario ");}
else if (digit == 7){
System.out.println(" Registered in Pacific region ");}
else if (digit == 9){
System.out.println(" A temporary SIN ");}
else if (digit ==8 && digit ==0) {
System.out.println( "Not used");
}}
System.out.println(" *** End of program *** ");
}
else
{
System.out.println ("Error message goes here. Here you can tell them that you want them to enter an integer and not a string.");
}
}
}
CodePudding user response：
Your problem is that Java is treating your Integer as 8 integers long. This is causing it to not be a valid input.
I made an if statement to check if it is treated as 8 characters long and if its 8 long and the first character is a 0 it prints not used since phone numbers don't start with 0.
if(count != 9 && (String.valueOf(Math.abs((long)num)).charAt(0) == '0')){
System.out.println( "Not used");
}
Full Code
import java.util.Scanner;
public class FirstDigitSIN
{
public static void main(String[] args)
{
Scanner kb = new Scanner(System.in);
System.out.print("Enter a SIN number :" );
if(kb.hasNextInt()){
// code that you want executed if the input is an integer goes in here
int num = kb.nextInt();
int numCopy = num;
int digit =0;
int count = 0;
while(num != 0 ){
num = num/10;
count ;}
if(count != 9 && (String.valueOf(Math.abs((long)num)).charAt(0) == '0')){
System.out.println( "Not used");
}
else if(count != 9){
System.out.println("Invalid Entry"); }
else{
System.out.println( num );
while(numCopy>0){
digit = numCopy %10;
numCopy = numCopy/10;
}if (digit == 1){
System.out.println(" Registered in Atlantic Canada ");
}else if(digit == 2){
System.out.println(" Registered in Quebec ") ;
}else if (digit == 3){
System.out.println(" Registered in Quebec ");}
else if (digit == 4){
System.out.println(" Registered in Ontario ");}
else if (digit == 5){
System.out.println(" Registered in Ontario ");}
else if (digit == 6){
System.out.println(" Registered in Prairie Provinces, NWT, Nunavut, Northwest Ontario ");}
else if (digit == 7){
System.out.println(" Registered in Pacific region ");}
else if (digit == 9){
System.out.println(" A temporary SIN ");}
else if (digit ==8 && digit ==0) {
System.out.println( "Not used");
}}
System.out.println(" *** End of program *** ");
}
else
{
System.out.println ("Error message goes here. Here you can tell them that you want them to enter an integer and not a string.");
}
}
}
CodePudding user response：
Couple of things:
- To Avoid skipping these leading 0 use String rather than int to hold the input.
- Then use Regex pattern to validate that String contains only numbers (else throw error if not a number).
- As in your code you want to check the value of first digit in number entered by user, to retrieve that get first index from entered
String. - The last condition
digit == 8 && digit == 0should be replaced withdigit == 8 || digit == 0, as here we are checking equality of single value. And single value can't be equal to both 8 and 0.
Here is the code:
public class FirstDigitSIN {
private static final String NUMBERS = "[0-9] ";
// Compile the ReGex
private static final Pattern NUMBER_PATTERN = Pattern.compile(NUMBERS);
public static void main(String[] args) throws JsonMappingException, JsonProcessingException {
Scanner kb = new Scanner(System.in);
System.out.print("Enter a SIN number :");
if (kb.hasNext()) {
// code that you want executed if the input is an integer goes in here
String num = kb.next();
// using Pattern.matcher()
Matcher m = NUMBER_PATTERN.matcher(num);
// Return if the string
// matched the ReGex
if (m.matches()) {
int numCopy = Integer.valueOf(num);
int digit = 0;
if (num.length() != 9) {
System.out.println("Invalid Entry");
} else {
System.out.println(num);
int digit = Character.getNumericValue(num.charAt(0));
System.out.println(digit);
if (digit == 1) {
System.out.println(" Registered in Atlantic Canada ");
} else if (digit == 2) {
System.out.println(" Registered in Quebec ");
} else if (digit == 3) {
System.out.println(" Registered in Quebec ");
} else if (digit == 4) {
System.out.println(" Registered in Ontario ");
} else if (digit == 5) {
System.out.println(" Registered in Ontario ");
} else if (digit == 6) {
System.out.println(" Registered in Prairie Provinces, NWT, Nunavut, Northwest Ontario ");
} else if (digit == 7) {
System.out.println(" Registered in Pacific region ");
} else if (digit == 9) {
System.out.println(" A temporary SIN ");
} else if (digit == 8 || digit == 0) {
System.out.println("Not used");
}
}
System.out.println(" *** End of program *** ");
} else {
System.out.println(
"Error message goes here. Here you can tell them that you want them to enter an integer and not a string.");
}
} else {
System.out.println(
"Error message goes here. Here you can tell them that you want them to enter an integer and not a string.");
}
}
}