I have a header file provided by yaml-cpp library, yaml.h
yaml.h:
#include "yaml-cpp/parser.h"
#include "yaml-cpp/emitter.h"
#include "yaml-cpp/emitterstyle.h"
#include "yaml-cpp/stlemitter.h"
#include "yaml-cpp/exceptions.h"
#include "yaml-cpp/node/node.h"
#include "yaml-cpp/node/impl.h"
#include "yaml-cpp/node/convert.h"
#include "yaml-cpp/node/iterator.h"
#include "yaml-cpp/node/detail/impl.h"
#include "yaml-cpp/node/parse.h"
#include "yaml-cpp/node/emit.h"
main.cpp
#include "./lib/yaml-cpp/include/yaml.h"
int main()
{
YAML::Node config = YAML::LoadFile("config.yaml");
return 0;
}
All the header files are in the same directory (/home/user/application/libs/yaml-cpp/include)
, but the compiler is unable to find parser.h and all the other includes. Why is this so and how do I fix it?
I have tried using g -I/home/user/application/libs/yaml-cpp/include main.cpp
but that did not work.
I am on a linux environment. Everything works fine when the header files are kept in /usr/lib64, but I am not allowed to do that for this project.
CodePudding user response:
When you have a file yaml.h
that itself includes other files like this:
#include "yaml-cpp/parser.h"
Then the expected directory layout is as follows:
somewhere/
|
-- yaml.h
|
-- yaml-cpp/
|
-- parser.h
You are expected to pass -Isomewhere
to your compiler and use the header file yaml.h
like this in your own source code:
#include <yaml.h>