I have a list with the following structure:
l <- list(condition = "AND",
rules = list(list(id = "sex",
field = "sex"),
list(condition = "AND",
rules = list(
list(id = "species",
field = "species"),
list(condition = "AND",
rules = list(
list(id = "bill_length_mm",
field = "bill_length_mm")))))),
valid = TRUE)
and I would like to convert to this structure
goal <- list(
list(id = "sex",
field = "sex"),
list(id = "species",
field = "species"),
list(id = "bill_length_mm",
field = "bill_length_mm")
)
The solution would need to be flexible enough to handle more/less rules
elements. Any suggestions on how I can do this would be greatly appreciated!
CodePudding user response:
Using a recursive function with rrapply
library(rrapply)
out <- rrapply(l, condition = function(x, .xname)
.xname %in% c('id', 'field'), how = "flatten" )
out2 <- unname(split(as.list(out), cumsum(names(out) == "id")) )
-checking with expected output
> identical(goal, out2)
[1] TRUE
CodePudding user response:
It looks like you could use a recursive strategy here. This will look for lists that have an id
elemenet and will return them as a list.
get_fields <- function (x) {
if (is.list(x)) {
if (!is.null(x$id)) {
return(list(x))
} else {
unname(do.call("c", lapply(x, get_fields)))
}
} else {
NULL
}
}
dput(result<-get_fields(l))
# list(list(id = "sex", field = "sex"), list(id = "species", field = "species"),
# list(id = "bill_length_mm", field = "bill_length_mm"))