a not same as a 1 in Arrays in C ?-CodePudding

I just recently came across a case where a is not same as a 1. Please analyze the below snippet of code :

INPUT 1 :

int a[] = {11, 12};
int *p = a   1;
cout << *p;

OUTPUT 1:

INPUT 2 :

int a[] = {11, 12};
int *p =   a;
cout << *p;

OUTPUT 2 :

error: lvalue required as increment operand

Can somebody please explain to me the reason behind this problem ?

CodePudding user response：

In first Case: when you are passing name of the array i.e. a here , you are passing the address of first value stored in array so when : int *p = a 1; is executed it takes first value from array i.e 11 and then 1 is added to that value and output is 12 . this code wont give you any error as you are not changing anything about array or in array. In second case: you will get a compile time error " lvalue required as increment operand" . Here you are trying to increment the array and you cannot perform the increment operation on array.