employees =[
    {
        "name": "John Doe",
        "job": "Software Engineer",
        "City": "Vancouver",
        "age": 34,
        "status": "single"
    },
    {
        "name": "Alicia Smith",
        "job": "Director",
        "City": "New York",
        "age": 38,
        "status": "Married"
    }
] 

keys = ["name", "age"]


if "name" and "age" in employees:
 newDict = employees.pop("name" and "age")
 print(newDict)

CodePudding user response：

There are a few mistakes in your code. I believe that you're trying to remove the keys name and age from the dictionaries wherever present. Try the following:

employees = [
    {
        "name": "John Doe",
        "job": "Software Engineer",
        "City": "Vancouver",
        "age": 34,
        "status": "single"
    },
    {
        "name": "Alicia Smith",
        "job": "Director",
        "City": "New York",
        "age": 38,
        "status": "Married"
    }
]

newDict = []
for d in employees:   # First iterate over the dictionaries
    if "name" in d:   # If the key "name" is there in the dictionary
        d.pop("name") # Remove it
    if "age" in d:    # Check if "age" is there in the keys
        d.pop("age")  # Remove it too if present
    newDict.append(d) # Add the updated dictionary to our list
print(newDict)

CodePudding user response：

You can use a dict comprehension inside a list comprehension for a one-liner.

print([{k: v for k, v in d.items() if k not in keys} for d in employees])

If you want to perform it in multiple lines, you should make a copy of the dictionary before removing items from it. Otherwise, you would get the following error.

RuntimeError: dictionary changed size during iteration

CodePudding user response：

first you got two errors in the code the first one because the if statement is not correct that is why is not being executed. second you can't pop a dict inside array you got to choose each one and then pop them or put them in loop like this solution

employees =[ { "name": "John Doe", "job": "Software Engineer", "City": "Vancouver", "age": 34, "status": "single" }, { "name": "Alicia Smith", "job": "Director", "City": "New York", "age": 38, "status": "Married" } ]
newDict = []
for i in employees:
    if "name" and "age" in i:
        i.pop("name" and "age")
        newDict.append(i)
print(newDict)