I would like to get the sum of only the odd numbers stored in array and it shall pass as argument to the function. Here is my code:

def sum_odd(arr):
    sum = 0
    for i in arr:
        if(i%2==1):
            sum =i
    return(arr)

nums = (input("Enter 10 numbers: "))
arr = list(map(int, nums.split()))

print("The sum of all odd numbers is: ", sum_odd)

but when I print it only says:

The sum of all odd numbers is: <function sum_odd at 0x0000025BE2A37F70>

I would also like to try to input an error message if the user inputs beyond 10 numbers.

CodePudding user response：

First of all you should give your function an argument when you call it Second, inside your function you're returning the array not the result. I changed your code and here it is:

def sum_odd(arr):
    ans = 0
    for i in arr:
        if i%2 == 1:     # if it's odd. 
            ans  = i     # keep adding up
    return ans

arr  = [int(x) for x in input("Enter 10 numbers: ").split()]

print("The sum of all odd numbers is: ", sum_odd(arr))

Input:

Enter 10 numbers: 1 2 3 4 5 6 7 8 9 10

output:

The sum of all odd numbers is:  25

CodePudding user response：

Please change the following two things.

1. The sum_add function needs to be called. That is, change sum_add to sum_add(arr)

print("The sum of all odd numbers is: ", sum_odd(arr))

2. sum_add function is returning the array itself instead of the sum. Please change from return(arr) to return(sum)

These changes should solve the issues here