The task is to exclude value if one contains :. The value also must include at least 1 word character.

matched string values are:

'   h-73 \r\n\t'
'   hey'
'hi  '
'7'

not matched values are:

'    \r\n\t' // neither letter not digit
'    ' // neither letter not digit
'  sds:  \r\n\t' // :

To exclude : I'd use /^[^:] $/ to filter word characters I'd use /\w /.

I have no idea how to use them together in the same regex because scope of each condition should be whole string.

CodePudding user response：

The regex that matches your specifications is

/^[^\w:]*\w[^:]*$/

Details:

• ^ - start of string
• [^\w:]* - zero or more chars other than word and : chars
• \w - one word char
• [^:]* - any chars, zero or more occurrences, other than a colon
• $ - end of string.

JavaScript demo:

const texts = ['   h-73 \r\n\t','   hey','hi  ','7','    \r\n\t','    ','  sds:  \r\n\t'];
const re  = /^[^\w:]*\w[^:]*$/;
for (const text of texts) {
    console.log("'" text "'", '=>', re.test(text));
}

<iframe name="sif1" sandbox="allow-forms allow-modals allow-scripts" frameborder="0"></iframe>

NOTE: You could also use /^[^:]*\w[^:]*$/, but this regex grabs non-colons from the start of string as many times as possible, and then backtracks to find a word char, which is less efficient. So, the \w in the first negated character class is welcome.