how to send post request in python for this curl command-CodePudding

how to send a POST request in python equivalent with this curl command

curl -u "YOUR_USERNAME:YOUR_ACCESS_KEY" \
-X POST "https://api-cloud.browserstack.com/app-automate/upload" \
-F "url=https://www.browserstack.com/app-automate/sample-apps/android/WikipediaSample.apk"

I tried code below:

resp=requests.post(URL,headers= 
    {'YOUR_USERNAME:YOUR_ACCESS_KEY'},
  data=https://www.browserstack.com/app-automate/sample-apps/android/WikipediaSample.apk")

and its not working.

I don't know how to send this line "url=https://www.browserstack.com/app-automate/sample-apps/android/WikipediaSample.apk" in POST request. "url=https://www.browserstack.com/app-automate/sample-apps/android/WikipediaSample.apk" this is the public url of apk. and want to upload at this url "https://api-cloud.browserstack.com/app-automate/upload"

CodePudding user response：

Use requests

You can do like this :

import requests

files = { 'file': ('url=https://www.browserstack.com/app-automate/sample-apps/android/WikipediaSample.apk', 
open('url=https://www.browserstack.com/app-automate/sample-apps/android/WikipediaSample.apk', 
'rb')),}
URL = 'https://api-cloud.browserstack.com/app-automate/upload'
response = requests.post(URL, files=files, auth=('YOUR_USERNAME', 'YOUR_ACCESS_KEY'))
print (response.text)

It should work fine now.

CodePudding user response：

    import requests

    files = {
        'data': (None, '{"url": "https://www.browserstack.com/app- 
    live/sample-apps/android/WikipediaSample.apk"}'),
    }

    response = requests.post(
        'https://api-cloud.browserstack.com/app-live/upload', 
        files=files, 
        auth=('USERNAME', 'ACCESS_KEY')
    )