If I have a list of split arguments seperated by spaces, how would I join the ones within qoutes bac-CodePudding

My argument parser works by taking every word in your string and splitting it by the spaces. I want to put the arguments back together, but only if it is between "'s, like this

My argument list would look like this:

['"Hello', 'there', ',', 'my', 'friend!"', '"1', '2', '3"']

And I want to put them back together:

['"Hello there, my friend!"', '"1 2 3"']

But I can have multiple strings, and store each one of these full strings in an array, let's call it fullStrings.

CodePudding user response：

You could try something like this but it does include a space after the there i.e. there , which may not be suitable for you?

output = ['"Hello there , my friend!"', '"1 2 3"']

const words = ['"Hello', 'there', ',', 'my', 'friend!"', '"1', '2', '3"']
let fullString = '';

words.forEach((word, index) => {
  fullString  = (index > 0)? ` ${word}`:`${word}`; //create sentence
});

// split on '"' and filter out empty values
const fullStrings = fullString.split('"').filter(Boolean).map((r)=>{
  let result = (r != ' ')? `"${r}"`: null;
  return result;
}).filter(Boolean); //remove null

console.log(fullStrings);

CodePudding user response：

Kind of simple solution in declarative way

Using: Array#join String#replaceAll String#split

const result = ['"Hello', 'there', ',', 'my', 'friend!"', '"1', '2', '3"']
  .join(' ')                  // '"Hello there , my friend!" "1 2 3"'
  .replaceAll(' ,', ',')      // '"Hello there, my friend!" "1 2 3"'
  .replaceAll('" "', '"" ""') // '"Hello there, my friend!"" ""1 2 3"'
  .split('" "');              //['"Hello there, my friend!"', '"1 2 3"']
  

result.map((o) => console.log(o));

console.log(result);

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