Regex exclude characters from inner group match-CodePudding

I would like to integrate an exclude from inner group email regex match, i ve tryed already to exclude character < & > to exclude from group [\p{L}\p{S}][^<>] not successful.

^(?!.{256})(?:[\p{L}] (?:\.[\p{L}] )*@(?:(?:[\p{L}](?:[\p{L}\p{S}]*[\p{L}])?\.) [\p{L}](?:[\p{L}\p{S}]*[\p{L}])?|\[(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\]))$

CodePudding user response：

Using \p{S} can also match < and > If you don't want to match those, and keep using the character class [\p{L}\p{S}] you can use a negative lookahead to rule out the matches for those characters.

As the part before @ can not match angle brackets, you can add another negative lookahad to the start of the string asserting not < or > to the right.

^(?!\S*[<>])(?!.{256})(?:[\p{L}] (?:\.[\p{L}] )*@(?:(?:[\p{L}](?:[\p{L}\p{S}]*[\p{L}])?\.) [\p{L}](?:[\p{L}\p{S}]*[\p{L}])?|\[(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\]))$

See a regex demo.

CodePudding user response：

An in-line approach is to exclude <> from the symbol class. In order to do that replace [\p{L}\p{S}] in 2 places with (?:\p{L}|[^\P{S}<>])

Where the \p{L} has to be explicitly or'd.
However inside classes each item is or'd anyway, and not too efficiently.

^(?!.{256})(?:[\p{L}] (?:\.[\p{L}] )*@(?:(?:[\p{L}](?:(?:\p{L}|[^\P{S}<>])*[\p{L}])?\.) [\p{L}](?:(?:\p{L}|[^\P{S}<>])*[\p{L}])?|\[(?:(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\.){3}(?:25[0-5]|2[0-4][0-9]|[01]?[0-9][0-9]?)\]))$

https://regex101.com/r/6OPVA8/1

CodePudding user response：

Use a negated intersection:

[\p{L}\p{S}&&[^<>]]

Which subtracts <> characters, specified in an inner character class, from the outer character class of \p{L}\p{S}.