Given I have two objects, what is the simplest way to compare if they have at least one property matching (some or any)? I am not looking for a full match of a whole object A within object B but a match of partial object A within object B.

{
 name: "John",
 age: 23,
 city: "London"
}
// and 
{
 name: "Craig",
 age: 47,
 city: "London"
}
// returns true

{
 name: "Adrian",
 age: 32,
 city: "Sofia"
}
// and 
{
 name: "Tom",
 age: 44,
 city: "Oslo"
}
// returns false

I have tried several partial match functions by lodash (isMatch) but they seem to perform all-to-some or all-to-all matches, whereas I am looking for some-to-some.

CodePudding user response：

If you're simply checking if they have anything in common:

const john = { name: "John", age: 23, city: "London" }
const craig = { name: "Craig", age: 47, city: "London" }

const adrian = { name: "Adrian", age: 32, city: "Sofia" }
const tom = { name: "Tom", age: 44, city: "Oslo" }

function hasAnythingInCommon(obj1, obj2) {
  for (const key in obj1) {
    if(obj1[key] === obj2[key]) return true
  }
  return false
}

console.log(hasAnythingInCommon(john, craig))
console.log(hasAnythingInCommon(adrian, tom))

Short explanation:

1. for (const key in obj1): Loop through all the keys in the first object.
2. if(obj1[key] === obj2[key]) return true: If the two objects agree on the value they have on one of these keys, return true immediately.
3. return false: If you get through the entire loop without returning true, then they have nothing in common, and we return false.

CodePudding user response：

The easiest way is to simply list out all attributes as comparisons:

const compare = (a, b) => a.name === b.name || a.age === b.age || a.city === b.city;

A more generic version would be:

const compare = (a, b) => Object.entries(a).some(([key, value]) => value === b[key]);