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Summation series in r

Time:01-27

I am currently trying to simplify this summation, I am new to R

data:

Lx = c(5050.0, 65.0, 25.0, 19.0, 17.5, 16.5, 15.5, 14.5, 13.5, 12.5, 6.0, 0.0)

summation series

Tx = c(sum(Lx[1:12]),sum(Lx[2:12]),sum(Lx[3:12]),sum(Lx[4:12]),
       sum(Lx[5:12]),sum(Lx[6:12]),sum(Lx[7:12]),sum(Lx[8:12]),
       sum(Lx[9:12]),sum(Lx[10:12]),sum(Lx[11:12]),sum(Lx[12:12]))

Thank you

CodePudding user response:

You can do:

rev(cumsum(rev(Lx)))

[1] 5255.0  205.0  140.0  115.0   96.0   78.5   62.0   46.5   32.0   18.5    6.0    0.0

Or alternatively, using Reduce():

Reduce(` `, Lx, right = TRUE, accumulate = TRUE)

[1] 5255.0  205.0  140.0  115.0   96.0   78.5   62.0   46.5   32.0   18.5    6.0    0.0

CodePudding user response:

Using a for loop:

Tx_new <- vector(length = length(Lx))
for (i in 1:length(Lx)) {
  
  Tx_new[i] <- sum(Lx[i:length(Lx)])
  
}

CodePudding user response:

A possible solution, using sapply:

sapply(1:12, function(x) sum(Lx[x:12]))

#>  [1] 5255.0  205.0  140.0  115.0   96.0   78.5   62.0   46.5   32.0   18.5
#> [11]    6.0    0.0

CodePudding user response:

Please try the following code:

Lx = c(5050.0, 65.0, 25.0, 19.0, 17.5, 16.5, 15.5, 14.5, 13.5, 12.5, 6.0, 0.0)

l=length(Lx)

aa=list()

for(i in 1:l)

{ 
  x=sum((Lx[i:l]))

  aa=append(aa,x)
  
}

all the values after summation will be in the list "aa".

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