I am sure this question has been asked before and has an easy solution, but I can't seem to find it.
I am trying to conditionally replace the logical value of a variable based on the value of other variables in the data. Specifically, I am trying to determine eligibility based on survey responses.
I have created my eligibility variable in dataframe screen:
screen$eligible <- ifelse (
(screen$age > 17 & screen$age < 23)
& (screen$alcohol > 3 | screen$marijuana > 3)
& (screen$country == 0 | screen$ageus < 12)
& (screen$county_1 == 17 | screen$county_1 == 27 | screen$county_1 == 31)
& (screen$residence_1 == 47),
TRUE,
FALSE)
And now, based on study changes, I would like to further limit eligibility. I tried the code below, and it works in part, but it appears that I am introducing NAs to my eligibility variable and missing out on folks who should be eligible.
screen$eligible <- ifelse( screen$eligible ==TRUE, ifelse(
(screen$gender_1 == 1 & screen$age > 18)
|(screen$gender_8 == 1 & screen$age > 20),
FALSE, TRUE), FALSE)
I ultimately want TRUE or FALSE values.
Two questions
- Is there a clearer or more concise way to update the code to update my eligibility requirements?
- Any ideas as to why I might be introducing NAs?
CodePudding user response:
1. Is there a clearer or more concise way to update the code to update my eligibility requirements?
If you ever find yourself writing x = ifelse(condition, TRUE, FALSE)
, as you are here -- that's equivalent to just writing x = condition
. Also, your three county_1 == x
statements can be replaced with one county_1 %in% c(x, y, z)
. So your first code block could be written as,
screen$eligible <- (screen$age > 17 & screen$age < 23)
& (screen$alcohol > 3 | screen$marijuana > 3)
& (screen$country == 0 | screen$ageus < 12)
& screen$county_1 %in% c(17, 27, 31)
& (screen$residence_1 == 47)
Likewise, your second codeblock could be simplified as:
screen$eligible <- screen$eligible
& ((screen$gender_1 == 1 & screen$age > 18)
| (screen$gender_8 == 1 & screen$age > 20))
2. Any ideas as to why I might be introducing NAs?
It's hard to say without seeing your data, but the NA
s probably indicate that one or more of your constituent variables (gender_1, gender_8, age) is NA
for some cases.
CodePudding user response:
continuing from what @zephryl wrote, an even more readable code is:
screen$eligible <- with(screen,
(age > 17 & age < 23)
& (alcohol > 3 | marijuana > 3)
& (country == 0 | ageus < 12)
& county_1 %in% c(17, 27, 31)
& (residence_1 == 47))
- to detect where are the NAs:
sapply(screen, anyNA)