We currently have a users
table with a one-to-many
relationship on a table called steps
. Each user can have either four steps or seven steps. The steps
table schema is as follows:
id | user_id | order | status
-----------------------------
# | # |1-7/1-4| 0 or 1
I am trying to query all of the users who have a status of 1
on all of their steps. So if they have either 4 or 7 steps, they must all have a status of 1.
I tried a join with a check on step 4 (since a step cannot be complete without the previous one being complete as well) but this has issues if someone with 7 steps completed step 4 but not 7.
select u.first_name, u.last_name, u.email, date(s.updated_at) as completed_date
from users u
join steps s on u.id = s.user_id
where s.order = 4 and s.status = 1;
CodePudding user response:
The bool_and
aggregate function should help you to identify the users with all their steps at status = 1 whatever the number of steps.
Then the array_agg
aggregate function can help to find the updated_at
date associated to the last step for each user by ordering the dates according to order DESC
and selecting the first value in the resulting array [1]
:
SELECT u.first_name, u.last_name, u.email
, s.completed_date
FROM users u
INNER JOIN
( SELECT user_id
, (array_agg(updated_at ORDER BY order DESC))[1] :: date as completed_date
FROM steps
GROUP BY user_id
HAVING bool_and(status :: boolean) -- filter the users with all their steps status = 1
) AS s
ON u.id = s.user_id