Filter a dictionary of dictionaries by another dictionary-CodePudding

I have tried this answer for my problem: Match dictionary by a filter (other dictionary)

Here is the code I use :

    
mydict = {'foo' : 'bar', 'foo1' : {"sub_foo" : 'sub_bar', "sub_foo1" : "sub_bar1"}}

myfilter = {'foo1' : {"sub_foo" : "sub_bar"}}


setf = set(myfilter.items()) # save space
if setf == (set(mydict.items()) & setf): # if pass 
    print(mydict)

I get this error :

Traceback (most recent call last):
  File "c:\Users\basti\Documents\IVAO and VATSIM py wrapper\python-ivao\simple_test.py", line 29, in <module>
    setf = set(myfilter.items()) # save space
TypeError: unhashable type: 'dict'

I would like to have a way to tell if the filter sub_dict is included in the dict.

CodePudding user response：

IIUC, you could traverse myfilter and check if a value in it is a subset of the value with the same key in mydict:

for k1, v1 in myfilter.items():
    if isinstance(v1, dict):
        print(set(v1.items()).issubset(mydict.get(k1, {}).items()))
    elif isinstance(v1, (str, int, float)):
        print(v1 in mydict.get(k1, {}))

Output:

True

It returns True because the value under foo1 key in myfilter ({"sub_foo" : "sub_bar"}) exists in mydict as the same key-value pair in my_dict also under foo1 key.