Javascript regex remove trailing zeroes after decimal-CodePudding

I know this has been asked many times and I did find a solution, value.replace(/^([\d,] )$|^([\d,] )\.0*$|^([\d,] \.[0-9]*?)0*$/, "$1$2$3").

But... I'm no regex expert so I'm just curious as to why this doesn't work /[\.0] $/... 10 should return 10 but I just can't figure out how to exclude whole numbers that end with 0s.

1.7500, 1.1010, 1.0000, 10

1.75, 1.101, 1, 1

CodePudding user response：

You might shorten the pattern to match either a dot with only zeroes, or use a non greedy match for the digits with a capture group and match optional trailing zeroes.

If you want to match digits and comma's the first \d can also be [\d,] as you already have in your pattern.

If there should be at least a single digit after the dot, then the quantifier can be a plus .\d ?

^(\d )(?:\.0 |(\.\d*?)0 )$

See a regex 101 demo.

[
  "1.7500",
  "1.1010",
  "1.0000",
  "10"
].forEach(s =>
  console.log(s.replace(/^(\d )(?:\.0 |(\.\d*?)0 )$/, "$1$2"))
);