How to delete an element every 8 elements in a list of strings on python?-CodePudding

Suppose that you have a list of strings like the following one:

the_list = ['02:00', '  GBP', '', 'Construction Output (MoM) (Jan)', '1.1%', '0.5%', '2.0%', '',
            '02:00', '  GBP', '', 'U.K. Construction Output (YoY) (Jan)', '9.9%', '9.2%', '7.4%', '',
            '02:00', '  GBP', '', 'GDP (MoM)', '0.8%', '0.2%', '-0.2%', '',
            '02:00', '  GBP', '', 'GDP (YoY)', '10.0%', '9.3%', '6.0%', '',
            '02:00', '  GBP', '', 'Index of Services', '1.0%', ' ', '1.2%', '']

Which every 8 elements appears '', which is an empty string, and it happens to be the same empty string that exists next to the one called GBP

How could the_list variable be updated so that it deletes the '' element that appears every 8 elements in the array of strings?

CodePudding user response：

If I understood you correctly, you can use list-comprehension to filter out the values at specific index:

new_list = [word for idx, word in enumerate(the_list, 1) if idx % 8 != 0]
print(new_list)

Prints:

['02:00', '  GBP', '', 'Construction Output (MoM) (Jan)', '1.1%', '0.5%', '2.0%',
 '02:00', '  GBP', '', 'U.K. Construction Output (YoY) (Jan)', '9.9%', '9.2%', '7.4%',
 '02:00', '  GBP', '', 'GDP (MoM)', '0.8%', '0.2%', '-0.2%',
 '02:00', '  GBP', '', 'GDP (YoY)', '10.0%', '9.3%', '6.0%',
 '02:00', '  GBP', '', 'Index of Services', '1.0%', ' ', '1.2%']

CodePudding user response：

It's pretty simple:

del the_list[::8]  # or del the_list[7::8] if you try to delete the 7th element of each line

CodePudding user response：

just use this code to find the element that you want to delete in that case is empty string, in python is a false string so

for x in the_list:
    if not x:
        the_list.remove(x)