Changing name of the file to parent folder name-CodePudding

The

Regardless the file extension I would like to have the name of this file to be exactly the same as its parent folder, i.e. when considering folder 2023-10-18 I would like to have the file inside 2023-10-18 instead of occultation....

I tried to rename the multiple files by using this thread:

CodePudding user response：

You need to save it to a file (for example, rename.py) and call it using the python interpreter with an additional parameter - the name of the parent directory for which you want to rename the files in its subdirectories. For example: "python rename.py parent_dir". The directory name can be either absolute or relative. As an additional parameter, you can also specify the key for saving the extension when renaming a file (0 - do not save, 1 - save). Extensions are not saved by default. Here's an example with saving an extension: "python rename.py parent_dir 1".

Script in rename.py:

import os import sys def rename_first_file_in_dir(dir_path, new_file_name, keep_extension = False): for current_file_name in os.listdir(dir_path): current_file_path = os.path.join(dir_path, current_file_name) # full or relative path to the file in dir if not os.path.isfile(current_file_path): break # rename only base name of file to the name of directory if keep_extension: file_extension = os.path.splitext(current_file_name)[1] if len(file_extension) > 0: new_file_name = new_file_name file_extension new_file_path = os.path.join(dir_path, new_file_name) print("File " current_file_name " renamed to " new_file_name " in " os.path.basename(dir_path) " directory"); os.rename(current_file_path, new_file_path) # exit after first processed file break if len(sys.argv) < 2: print("Usage: python " os.path.basename(__file__) " <directory> [keep_files_extensions]") # help for usage exit(0) scan_dir = sys.argv[1] keep_extension = False if len(sys.argv) < 3 else not (int(sys.argv[2]) == 0) # optional parameter 0 - False, 1 - True, by default - False if not os.path.exists(scan_dir): print("Error: directory " scan_dir " does not exists") exit(-1) if not os.path.isdir(scan_dir): print("Error: file " scan_dir " is not a directory") exit(-1) print("Scanning directory " scan_dir) for file_name in os.listdir(scan_dir): # walk through directory file_path = os.path.join(scan_dir, file_name) if os.path.isdir(file_path): rename_first_file_in_dir(file_path, file_name, keep_extension)

CodePudding user response：

Here a sample code using pathlib module. Be sure to modify the base_folder.

""" rename_filename.py Rename filename inside the folders. https://stackoverflow.com/questions/71408697/changing-name-of-the-file-to-parent-folder-name Example: base_folder F:/Tmp/s13/ sub_folders F:/Tmp/s13/2022-05-01 F:/Tmp/s13/2022-08-01 files under subfolder F:/Tmp/s13/2022-05-01/aa.txt F:/Tmp/s13/2022-08-01/bb.txt Usage: Be sure to modify first the "base_folder" value in the main() command lines: python rename_filename.py or python3 rename_filename.py """ from pathlib import Path # python version >= 3.4 def rename_file(base_folder): """ Rename the filename of the file under the sub-folders of the base_folder. """ base_path = Path(base_folder).glob('*/*') # Get the file path in every sub-folder. for file in base_path: # print(file) sub_folder_abs_path = file.parent # sub-folder path, F:/Tmp/s13/2022-05-01 sub_folder_name = file.parent.name # sub-folder name, 2022-05-01 # Rename the file to sub-folder name. new_file = Path(sub_folder_abs_path, sub_folder_name) file.rename(new_file) def main(): # Change the base folder according to your case. base_folder = 'F:/Tmp/s13/' rename_file(base_folder) if __name__ == '__main__': main()