I want to display one image at a time this is the code i have written for 2 image. But it does not work as i want to. I want that after the 1st has completely finished then it takes 10 sec delay then run the second ad.

def ad():
    global pop
    pop=Toplevel(root)
    pop.geometry('1600x900')
    global pic

    pic=PhotoImage(file='ad.png')

    label_pop = Label(pop, image=pic)
    label_pop.grid()

    pop.overrideredirect(1)
    pop.after(5000, lambda: pop.destroy())


    
    #ad 2
    global pop2
    pop2=Toplevel(root)
    pop2.geometry('1600x900')
    global pic2

    pic2=PhotoImage(file='j..png')

    label_pop2 = Label(pop2, image=pic2)
    label_pop2.grid()

    pop2.overrideredirect(1)
    pop2.after(5000, lambda: pop2.destroy())
    root.after(15000, ad)




root.after(5000,ad)

CodePudding user response：

Create a cycle list of the images you want to show using itertools.cycle() and then you can get the next image using next().

Below is an example:

...
from itertools import cycle

...

# a cycle list of images you want to show
imagelist = cycle(['ad1.png', 'ad2.png', ...])

def ad():
    pop = Toplevel(root)
    pop.geometry('1600x900')
    pop.overrideredirect(1)

    pic = PhotoImage(file=next(imagelist)) # get next image using next()

    label_pop = Label(pop, image=pic)
    label_pop.grid()
    label_pop.image = pic  # save reference of image to avoid garbage collection

    root.after(5000, pop.destroy)
    root.after(15000, ad)

root.after(5000, ad)
...

CodePudding user response：

1. You need to use different file names for each image.
2. You can use the time module and specifically time.delay() for the delay.