Why function gives difference results with print and return-CodePudding

If i code:

a = [56, 2, 5, 2, 5, 2, 6, 2, 6, 2, 56, 2, 6, 2, 52, 5, 2]


def func1(a3):
    for i in range(len(a)-1):
        if a[i]   a[i 1] == 58:
            print(a[i])
func1(a)

I get in output: 56 2 56

But if i code return a[i] instead of print(a[i]) i get only first suitable number How can i fix it?

CodePudding user response：

Your code exits out of the function when it encounters a return statement. So the following iterations dont happen. If you need a list of values that you were going to print, take a empty array and then append to it whenever you want to print and then return that list when the for loop is over

a = [56, 2, 5, 2, 5, 2, 6, 2, 6, 2, 56, 2, 6, 2, 52, 5, 2]


def func1(a3):
    ans = []
    for i in range(len(a)-1):
        if a[i]   a[i 1] == 58:
            ans.append(a[i])
    return ans
func1(a)

CodePudding user response：

The return function causes your function to "stop running", returning the value passed in parameter. If you want to return more than the first element, you might want to create a list in which you append the desired elements.

a = [56, 2, 5, 2, 5, 2, 6, 2, 6, 2, 56, 2, 6, 2, 52, 5, 2]
def func1(a3):
    result = []
    for i in range(len(a)-1):
        if a[i]   a[i 1] == 58:
            result  = [a[i]]
func1(a)