There are two types file.

1. Book1_20190715_1A.gz,

2. Book1_20190715A.gz,

3. Book2_20190716_1A.gz,

4. Book2_20190716A.gz

   Here, 2019 is year 07 is month & 15 is date also 16. Also here is two type file _1A & A.

   Need to Transfer Date-wise in Folder. Also Need to transfer different folder for different type file like _1A & A

If I grep like *_1A then it transfer _1A folder But if *A then it transfer A also _1A.

What I do now. Please Help me.

CodePudding user response：

Your question is not very clear, but this is what I think you are looking for:

#!/bin/bash

find . -type f -name "Book*" -print0 | while IFS= read -r -d '' file
do
    # Remove "Book1_"
    tempdirname=${file#*_}
    # Remove ".gz"
    dirname=${tempdirname%\.*}
    echo "$dirname"
    if [[ ! -d "$dirname" ]]
    then
        mkdir "$dirname"
    fi
    /bin/mv "$file" "$dirname"
done

• the find lists all files named Book* and sends that list to a while loop.
• from the filename, extract the directory name using variable expansion. First remove "Book1_", then remove ".gz". This leaves you with the date, and the "_1A" portion, if it is there.
• then create the directory if it does not already exist.
• move the file to the directory.

CodePudding user response：

You can move the *_1A.gz files first:

mv ./*_1A.gz dir_1A/
mv ./*A.gz dirA/

update:

If you prefer, you can make the globs a little more specific:

mv ./*_????????A.gz dirA/
mv ./*_????????_1A.gz dir_1A/

^{note: in globbing, ? means any character}

Or more accurate but longer:

d='[[:digit:]]'
mv ./*_$d$d$d$d$d$d$d${d}A.gz dirA/
mv ./*_$d$d$d$d$d$d$d${d}_1A.gz dir_1A/