Add dictionary key-values to all keys of another dictionary-CodePudding

I am trying to add the value of a dictionary that has only one key to all keys of another dictionary but my dictionaries have different keys. I want to do that using a loop because my original dictionary has more than 100 keys.

Here is an example of the dictionaries (dict2 should be added to each key of dict1):

dict1 = {
     'a': 3.84,
     'b': 4.9,
     'c': 6.7}


dict2={'value': {0: 1,
                 1: 6,
                 2: 10,
                 3: 2}}

For clarification, the dict2 should have only one key ('value'). The dict2 was created from a csv data frame, I tried to remove the line indexes but didn't find a way.

The "final" dictionary should have the value from dict1 and dict2 but without the "line indexes" of dict2. The final dictionary should look like this:

I tried many ways to do that using append(), update() but it didn't work. I also tried to use the dict2 as an array but it didn't work too.

Thanks for any help!

CodePudding user response：

You have to make the values for each key in dict3 a list since you can't have multiple values for one key. Here is a possible solution:

dict1 = {'a': 3.84, 'b': 4.9, 'c': 6.7}
dict2 = {'value': {0: 1, 1: 6, 2: 10, 3: 2}}

def dict_merge(dict1, dict2):
    dict3 = {}
    for key in dict1:
        dict3[key] = [dict1[key]]
        for key2 in dict2["value"]:
            dict3[key].append(dict2["value"][key2])
    return dict3


print(dict_merge(dict1, dict2))

Output:

{'a': [3.84, 1, 6, 10, 2], 'b': [4.9, 1, 6, 10, 2], 'c': [6.7, 1, 6, 10, 2]}

CodePudding user response：

If you want to create a list for every dict1 key, you can use this:

dict2_values = dict2["value"].values()
dict3 = {k: [v, *dict2_values] for k, v in dict1.items()}

We used special syntax of iterable unpacking here

l1 = [1,2]
l2 = [3,4]
print([*l1, *l2, 5]) # [1,2,3,4,5]